The Person Above Me II

6:

I know. That's like the third time i've seen this demonstration. Thanks, though, for resurfacing this subject in my mind. It's a beautiful subject; too bad there aren't many people interested in it.

Can you demonstrate the existence of aleph two, though? Hint: Aleph two is the cardinality of the set of all possible functions of RxR.
 
^^Is damn straight!

^Is currently discussing this "aleph" business, when he should be debating my theory of square roots (hint, see sig.)
 
The number of points in RxR has indeed an aleph one cardinality. But the number of all possible functions of RxR has the same cardinality as the number of all possible subsets of R, and the continuum hypothesis makes the following two statements (which, i think, are also appliable to finite sets, but i have to double-check that):

1. For any given set A with cardinality |A|, there is another set B which contains all the possible subsets of A (as long as |A|>0). The cardinality of B is |B|=2^|A|.

2. For infinite sets, aleph N+1 is equal to 2 ^ aleph N.

Thus, the cardinality of the set of all possible subsets of R is aleph 2. The continuum hypothesis has been proved to be non-provable, though, so it's up to you to believe all of this.
 
As to why the continuum hypothesis can't be proven, is it because the axiom of choice doesn't apply to it?

The axiom of choice - for every set we can provide a mechanism for choosing one member of any non-empty subset of the set.
 
^Is talking to the wrong person

La Rocque, Rampage... La Rocque