346) Because, actually, the two conditions are ok, it's just missing the first optional loop-variable initialization. The problem is that i is unsigned, so it never goes below 0. The loop is therefore infinite. (Wish I could have seen that earlier today)Originally posted by Kovenant84
338) Because, as far as I can tell/remember... for loops always had 3 conditions (that might be me being stupid tho)...
~Kovenant
Originally posted by Iron-Flames
341. Because I'm 15, Meghan is going to spend the night at my house tomorrow night, and I am going to get laid...and she wants to fuck to Damage Done. No Joke...